3t(cubed)-192t=0?
回答 (4)
2008-04-02 6:30 pm
✔ 最佳答案
3t (t² - 64) = 03t (t - 8) (t + 8) = 0
t = 0 , t = 8 , t = - 8
2008-04-02 11:05 pm
3t^3 - 192t = 0
3t(t^2 - 64) = 0
3t(t + 8)(t - 8) = 0
3t = 0
t = 0
t + 8 = 0
t = -8
t - 8 = 0
t = 8
â´ t = 0 , -8 , 8
3t(t^2 - 64) = 0
3t(t + 8)(t - 8) = 0
3t = 0
t = 0
t + 8 = 0
t = -8
t - 8 = 0
t = 8
â´ t = 0 , -8 , 8
2008-04-02 11:04 pm
3t^3 - 192t = 0
3t*(t^2 - 64) = 0
3t*[(t - 8)(t + 8)] = 0
Set each equal to 0:
3t = 0
t = 0
and
t - 8 = 0
t = 8
and
t + 8 = 0
t = -8
Therefore, t = 0, ±8
3t*(t^2 - 64) = 0
3t*[(t - 8)(t + 8)] = 0
Set each equal to 0:
3t = 0
t = 0
and
t - 8 = 0
t = 8
and
t + 8 = 0
t = -8
Therefore, t = 0, ±8
2008-04-02 11:03 pm
3t^3 = 192t
3t^2 = 192
t^2 = 192 / 3 = 64
t = sqrt 64 = 8
3t^2 = 192
t^2 = 192 / 3 = 64
t = sqrt 64 = 8
收錄日期: 2021-05-01 10:21:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080402080015AA31tNT