更新1:
can u explain more on the integration........by the way, you integration seens wrong......
更新2:
how do u integrate ∫xsin(x^2) dx ???
math problem 01
回答 (1)
2008-04-03 12:17 am
✔ 最佳答案
∫∫sin(x^2) dxdy=∫∫sin(x^2)dydx [y from 0 to x][x from 0 to 1]
=∫xsin(x^2) dx [from 0 to 1]
=1/2∫sin(x^2) d(x^2)
=-1/2cos(x^2) [0,1]
=(-1/2)(cos1-1)
=(1/2)(1-cos1)
2008-04-03 11:07:50 補充：
use substitution
d(x^2)=(2x)dx
收錄日期: 2021-04-26 13:05:26
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080402000051KK01064