how do you factor this?
回答 (6)
2008-04-01 4:01 pm
✔ 最佳答案
4x^2 - 1= (2x - 1)(2x + 1)
2008-04-01 11:02 pm
a^2 - b^2 = (a + b)(a - b)
4x^2 - 1
= (2x + 1)(2x - 1)
4x^2 - 1
= (2x + 1)(2x - 1)
2008-04-01 11:01 pm
4x^2-1=
=4(x^2-1/4)=4(x-1/2)(x+1/2)
=4(x^2-1/4)=4(x-1/2)(x+1/2)
2008-04-01 11:00 pm
a^2-b^2=(a-b)(a+b)
(2x)^2-(1)^2 = (2x-1)(2x+1)
(2x)^2-(1)^2 = (2x-1)(2x+1)
2008-04-01 11:00 pm
(2x+1)(2x-1)
2008-04-01 11:00 pm
Remember that a^2 - b^2 factors into (a+b)(a-b).
You can think of this as (2x)^2 - 1^2, which means it factors into
(2x + 1)(2x - 1)
You can think of this as (2x)^2 - 1^2, which means it factors into
(2x + 1)(2x - 1)
收錄日期: 2021-05-01 10:21:02
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https://hk.answers.yahoo.com/question/index?qid=20080401075628AAipULM