更新1:
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更新2:
please show your work
expand (2x-5)^2?
回答 (5)
2008-04-01 3:38 pm
✔ 最佳答案
(2x - 5)(2x - 5)4x² - 20x + 25
2008-04-01 3:37 pm
(2x-5)^2
= (2x-5)(2x-5)
= 4x^2 - 10x - 10x + 25
= 4x^2 - 20x + 25
= (2x-5)(2x-5)
= 4x^2 - 10x - 10x + 25
= 4x^2 - 20x + 25
2008-04-01 3:42 pm
(2x - 5)^2
= (2x - 5)(2x - 5)
= 2x*2x - 5*2x - 2x*5 + 5*5
= 4x^2 - 10x - 10x + 25
= 4x^2 - 20x + 25
= (2x - 5)(2x - 5)
= 2x*2x - 5*2x - 2x*5 + 5*5
= 4x^2 - 10x - 10x + 25
= 4x^2 - 20x + 25
2008-04-01 3:42 pm
(2x-5)^2=
(2x-5)(2x-5)=
4x^2-10x-10x+25=
4x^2-20x+25
;-)
(2x-5)(2x-5)=
4x^2-10x-10x+25=
4x^2-20x+25
;-)
2008-04-01 3:42 pm
(2x - 5)^2
(2x - 5)(2x - 5)
Use FOIL
First, 4x^2
Outside, -10x
Inside, -10x
Last, 25
The answer is
4x^2 - 20x + 25
(2x - 5)(2x - 5)
Use FOIL
First, 4x^2
Outside, -10x
Inside, -10x
Last, 25
The answer is
4x^2 - 20x + 25
收錄日期: 2021-05-01 10:18:36
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