(x^2 +6x -7)/(x -1) show your work?

(x + 7)(x - 1)
-----------------
(x - 1)

x + 7

The numerator can be factored as

(x+7)(x-1)

Therefore, the expression can be rewritten as

(x+7)(x-1)/(x-1) which by cancellation is

(x+7)

However, in subsequent work with this expression, you must not forget that x cannot equal 1 as the cancellation is disallowed for that value

(x^2 +6x -7)/(x -1)
(x^2 +7x-x -7)/(x -1)
(x{x+7}-1{x+7})/(x -1)
({x+7}{x-1})/(x -1)

so cancelling out x-1, we get
x+7

(x-1)(x+7)/(x-1)
Simplify by crossing out the two (x-1). What u r left with is (x+7)/1 or just (x+7). Good luck!

(x^2 + 6x - 7)/(x - 1)

The numerator factors to
(x + 7)(x - 1)/(x - 1)

Cancel the x - 1 in the numerator with that of the denominator and the answer is

x + 7

(x^2+6x-7)=(x-1)(x+7)

(x-1)(x+7)/((x-1)=(x+7)

(x^2 +6x -7)/(x -1)
=
(x+7)(x-1)/(x -1)
=
x+7
.

Factor the numerator
(x+7)(x-1) / (x-1)
then you can reduce to just
x+7

If the original was a function then 1 is still not in the domain.

(x^2 + 6x - 7)/(x - 1)
= (x + 7)(x - 1)/(x - 1)
= (x + 7)/1
= x + 7

a million) First you could desire to enhance the brackets. 2 - 10x = (3x-7)(x+a million) 2 - 10x = 3x(x +a million) - 7(x + a million) 2 - 10x = 3x² + 3x - 7x - 7 Now convey each and every thing to a minimum of one part. 0 = 3x² + 3x + 10x - 7x - 7 - 2 Simplify 0 = 3x² + 6x - 9 Now subsequently, we are able to easily divide each and every thing by ability of three 0/3 = 3x²/3 + 6x/3 - 9/3 0 = x² + 2x - 3 once you have it interior the format 0 = ax² + bx + c, to ingredient, you could desire to discover 2 numbers that upload as much as b, and multiply to equivalent a * c. subsequently, the two numbers would desire to upload to 2, and multiply to equivalent -3. we could try 3 and -a million: 3 + (-a million) = 2, and 3 * (-a million) = -3. So 3 and -a million are our 2 numbers. 0 = (x + 3)(x - a million) once you multiply something with a nil, the respond is 0. considering once you multiply those 2 brackets, you get an answer of 0, it ability that a variety of brackets equals 0. So x + 3 = 0 x = -3 or x - a million = 0 x = a million 2) x² = x + 6 as quickly as lower back, convey to a minimum of one part. 0 = -x² + x + 6 i'm going to divide each and every thing by ability of -a million, so the x² is by ability of itself. 0 = x² - x - 6 we want 2 numbers that upload as much as -a million and multiply to equivalent - 6. those numbers are -3 and 2. 0 = (x - 3)(x + 2) x - 3 = 0 x = 3 or x + 2 = 0 x = -2