(HCOOH)2 (g) ≒ 2HCOOH(g) Δ H =+52.42 kJmol^-1
Q: Determine the bond enthalpy of the hydrogen bond in the dimer molecules .
書中個answer 咁答...
A: Since each methanoic acid dimer is associated by 2 hydrogen bonds , the bond enthalpy of the hydrogen in the dimer molecules 52.42 / 2 =+26.21kJmol^-1
我唔明點解dimer 有2個hydrogen bonds @@~
Bond enthalpy
2008-04-02 2:18 am
回答 (1)
2008-04-02 9:12 am
✔ 最佳答案
In pure methanoic acid, methanoic acid (HCOOH) exists as dimers. Each dimer are formed by joining two HCOOH molecules with two hydrogen bonds. The structure of a dimer (with dotted lines to represent the hydrogen bonds) is shown in the following diagram:圖片參考：http://ndc.hkcampus.net/~ndc-007/HCOOH.jpg
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