tanθ = - 3/4 and sinθ>0.
find conθ + cscθ
有數唔識(a．maths)
2008-04-02 1:24 am
回答 (1)
2008-04-02 2:19 am
✔ 最佳答案
∵tanθ = - 3/4 and sinθ>0.∴θ is in the 2th quadrant.
cosθ=-4/5
csc θ=5/3
cosθ + cscθ=(-4/5)+(5/3)
=13/15
收錄日期: 2021-04-23 20:33:18
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