multiply the following:(x+3)(x+4)=?

x^2 + 7x + 12

x² + 4x + 3x + 12
x² + 7x + 12

= (x + 3)(x + 4)
= x² + 4x + 3x + 12
= x² + 7x + 12

Answer: x² + 7x + 12

the stairs: a million. Multiply the 1st 3x by ability of the 2d to get 9x^2 2. Multiply the 1st 3x by ability of the -4 to get -12x 3. Multiply the 4 by ability of the 2d 3x to get 12x 4. Multiply the 4 by ability of the -4 to get -sixteen 5. Line those domestic dogs up as: 9x^2 -12x + 12x - sixteen 6. notice that the -12x and the +12x upload to 0, so we are able to depart the two one in all them out. 7. 9x^2 - sixteen

(x+3) (x+4)
or x^2 +3x+4x +12
or x^2 +7x + 12
o.e. x Sq +7x+12

x^2+7x+12

(x + 3)(x + 4)
= x*x + 3*x + 4*x + 3*4
= x^2 + 3x + 4x + 12
= x^2 + 7x + 12

(X+3) (X+4)=
XxX= X2 (X square)
Xx4= 4X
3xX= 3X
3x4= 12

answer: X2 (X square) +7X+12