In 三角形ABC, (tanA - tanB) / (tanA +tanB) = (c-b)/c
ai) Using the sine law, prove that acosB - bcosA = c-b
ii) Hence, by cosine law, prove that a^2 = b^2 + c^2 -bc
b) Find 角BAC
收錄日期: 2021-04-14 19:48:11
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