Find the value of x: 3x - 3 /9 = 10x -1 /33?

Brackets should be used.
(3x - 3) / 9 = (10x - 1) / 33
99x - 99 = 90x - 9
9x = 90
x = 10

(3x-3)/9 = (10x-1)/33
3(x-1)/9 = (10x-1)/33
(x-1)/3 = (10x-1)/33
33(x-1) = 3(10x-1)
33x-33 = 30x-3
3x=30
x=10

i assume you mean (3x-9)/9 = (10x-1)/33 in which case ... you multiply each side by 33 and 9....

33(3x-9)=9(10x-1)

99x-297=90x-9
add 298 to both sides and subtract 90x from both sides
9x=288
divide by 9 on both sides
x=32

THE VALUE OF X=10.
3x10-3/9=10x10-1/33
27/9=99/3
3=3

I first concept a pair of polynomial which has degree <=5 when you consider which you gave 6 numbers. P(x) = 3 - 439/60*x + 161/24*x^2 - 5/3*x^3 + 7/24*x^4 - a million/60*x^5 the subsequent form would be P(7) = 129. Edit: it is not any further difficult to coach that if x is an integer then P(x) is likewise an integer. yet did you be attentive to if it is continuously like that? i desire to advise, you grant us P(a million)=p1, P(2)=p2,..., P(n+a million)=p_(n+a million) with p1, p2,..., p_(n+a million) integers. enable P(x) the polynomial of degree <= n which passes via all P(i)=p_i you gave. If x is an integer then P(x) is likewise an integer? i know quite a few you listed ultimate listed here are extremely reliable at math and probably you may help me, thank you! Vikram: i think of i elect it sluggish to comprehend why the interpolation in P(x) is continuously an integer. Your answer and links are very interesting, thank you. Vikram: i'm going to verify it now, that grew to alter into kind of you :-)

I got the same as Mrs. Wicher but the answer comes out to be x = 10 as well. Here are the steps:

1. Given: 3x - 3/ 9 = 10x -1/ 33

2. 3(x-1)/ 9 = 10x -1/ 33 cancel the 3 & 9 at this point and you get: 1(x-1)/ 3 = 10x - 1/ 33

3. We now know the common denominator is 33 cause 3 goes into 33 as 11 so now it looks this: 11(x-1)/ 33 = 10x - 1/ 33

4. Then we get: 11x - 11 = 10x - 1 cause 33 cancels out

5. Solve: 11x - 10x = -1 + 11

6. Answer: x = 10

(3x - 3)/9 = (10x - 1)/33
3x - 3 = (90x - 9)/33
99x - 99 = 90x - 9
99x - 90x = 99 - 9
9x = 90
x = 90/9
x = 10

(3x – 3)/9 = (10x – 1)/33
3(x – 1)/9 = (10x – 1)/33
(x – 1)/3 = (10x – 1)/33 --------------LCM 33
11(x – 1) = (10x – 1)
11 x – 11 = 10x – 1
x = 10
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