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In NaCl solution, NaCl gives Na+ and Cl- ions, and H2O is slightly ionized to give H+ and OH- ions. In the solutions, there are two types of cation (Na+ and H+) and two types of anion (Cl- and OH-).
When the NaCl solution is electrolysed, Na+ and H+ ions are attracted by the cathode. H+ ions are preferentially discharged because H+ ions are reduced more readily than Na+ ions.
2H+ + 2e- → H2
At the same time, Cl- and OH- ions are attracted by the anode. Cl- ions are preferentially discharged because Cl- ions are more concentrated than OH- ions.
2Cl- → Cl2 + 2e-
Before the electrolysis, the concentration and H+ ions and the concentration of OH- ions are equal. During the electrolysis, H+ ions are discharged (reacted) at the cathode, but OH- ions do not change at the anode. In other words, there is an excess amount of OH- ion left in the solution.
Consider CuSO4 solution. CuSO4 gives Cu2+ and SO42- ions, and H2O is slightly ionized to give H+ and OH- ions. In the solutions, there are two types of cation (Cu2+ and H+) and two types of anion (SO42- and OH-).
When the CuSO4 solution is electrolysed, Cu2+ and H+ ions are attracted by the cathode. Cu2+ ions are preferentially discharged because the Cu2+ ions are more concentrated than H+ ions.
Cu2+ + 2e- → Cu
At the same time, SO42- and OH- ions are attracted by the anode. OH- ions are preferentially discharged because OH- ions are oxidized more readily than SO42- ions.
4OH- → 2H2O + O2 + 4e-
Before the electrolysis, the concentration and H+ ions and the concentration of OH- ions are equal. During the electrolysis, OH- ions are discharged (reacted) at the anode, but H+ ions do not change at the cathode. In other words, there is an excess amount of H+ ion left in the solution.