更新1:
∫R[e^(-(R)/θ)][1-e^(-(R)/θ)]^(n-2) dR = 1 Reason? Computing ∫ (n-1)(R^2/θ)[e^(-(R)/θ)][1-e^(-(R)/θ)]^(n-2) dR is more difficult.
更新2:
The revised answer is problematic, can the mean be independent of n?
∫R[e^(-(R)/θ)][1-e^(-(R)/θ)]^(n-2) dR = 1 Reason? Computing ∫ (n-1)(R^2/θ)[e^(-(R)/θ)][1-e^(-(R)/θ)]^(n-2) dR is more difficult.
The revised answer is problematic, can the mean be independent of n?
收錄日期: 2021-04-23 13:01:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080328000051KK01316