3 consecutive integers with the sum of 267?

x + (x + 1) + (x + 2) = 267
3x = 264
x = 88

Integers are 88 , 89 , 90

x + (x + 1) + (x + 2) = 267
3x + 3 = 267
3x = 264
x = 88

88 , 89 , 90

If the integers are consecutive, that means that the average of the 3 numbers is the middle number. 3 times the middle number will also equal 267.

3x = 267
x = 89

So your numbers are 88, 89, 90.

1st No. (x):
x + x + 1 + x + 2 = 267
3x + 3 = 267
x + 1 = 89
x = 88

2nd No.:
= 88 + 1 or 89

3rd No.:
= 88 + 2 or 90

Answer: 88, 89 and 90 are the numbers.

Proof:
= 88 + 89 + 90
= 267

x + (x +1) + (x + 2) = 267

3x + 3 = 267
3x = 264
x = 88.

So x = 88, x+1 = 89 and x+2 = 90

So our integers are 88,89 and 90.

267 = 88 + 89 + 90

88+89+90=267

88 89 90

267 / 3 = 89

89 - 1 = 88
89 +- 0 = 89
89 + 1 = 90

88 89 90

equation : let x = 267

x/3 = n
3n=3n
3n =n + n + n
3n = n+n+n+1-1
3n=n+1+n+n-1
the three consecutive integer are n-1, n, and n+1