1 - 〔2x/ ( x-1/x)〕= ?
請各位列出步驟。Thank you!
2002 ce maths mc 37
2008-03-27 1:01 am
回答 (1)
2008-03-27 1:14 am
✔ 最佳答案
1 - 〔2x/ ( x-1/x)〕=1- [2x/[(x^2-1)/x]]
=1- [2x^2/(x^2-1)]
=[(x^2-1)- 2x^2]/(x^2-1)
=[- x^2-1]/(x^2-1)
=-(x^2+1)/(x^2-1)
參考: my math knowledge
收錄日期: 2021-04-29 21:46:23
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