if f(x) = x + 1 and g(x) = 2x^2 - 3?
回答 (8)
2008-03-25 10:51 am
✔ 最佳答案
f (g (x) ) = f (2x² - 3) = 2x² - 3 + 1 = 2x² - 2
2008-03-25 12:32 pm
In the function f(x) substitute x with the function g(x) = 2x^2 - 3
f(g(x)) = (2x^2 - 3) + 1
Now, just simplify
f(g(x)) = 2x^2 - 2
f(g(x)) = (2x^2 - 3) + 1
Now, just simplify
f(g(x)) = 2x^2 - 2
2008-03-25 12:30 pm
f(g(x)) = (2x^2 - 3) +1 = 2x^2 - 3 + 1 = 2x^2 + 2
2008-03-25 12:30 pm
to find f of g of x, put g(x) into equation for f(x)
f(x)= g(x) +1
f(g(x))= 2x^2-3+1
f(g(x))=2x^2-2
f(x)= g(x) +1
f(g(x))= 2x^2-3+1
f(g(x))=2x^2-2
2008-03-25 12:30 pm
f o g (x) = (2x^2-3) +1
= 2x^2-2
= 2x^2-2
2008-03-25 12:29 pm
That notation means to take g(x) and put it in for x in the f(x) equation.
So in f(x) = x + 1, I am going to throw out the x and put in 2x^2 - 3
{f o g}(x) = 2x^2 - 3 +1
Simplify.
{f o g}(x) = 2x^2 - 2
So in f(x) = x + 1, I am going to throw out the x and put in 2x^2 - 3
{f o g}(x) = 2x^2 - 3 +1
Simplify.
{f o g}(x) = 2x^2 - 2
2008-03-25 12:29 pm
substitute the g(x) into the equation of f(x)
[f of g](x)=(2x^2 - 3)+1
=2x^2 - 2
[f of g](x)=(2x^2 - 3)+1
=2x^2 - 2
2008-03-25 12:27 pm
f(g(x))=2x^2-2
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