completely factored, what are all possible solutions for x? Thanks so much! (x+3)(x+1)=24?
回答 (6)
2008-03-24 5:11 pm
✔ 最佳答案
[6](x+3)(x+1)=24
x^2+4x+3=24
x^2+4x+3-24=0
x^2+4x-21=0
(x+7)(x-3)=0
x= -7 or 3 ans
2008-03-25 12:13 am
(x + 3)(x + 1) = 24
x^2 + 3x + x + 3 - 24 = 0
x^2 + 4x - 21 = 0
(x + 7)(x - 3) = 0
x + 7 = 0
x = -7
x - 3 = 0
x = 3
â´ x = -7 , 3
x^2 + 3x + x + 3 - 24 = 0
x^2 + 4x - 21 = 0
(x + 7)(x - 3) = 0
x + 7 = 0
x = -7
x - 3 = 0
x = 3
â´ x = -7 , 3
2008-03-25 12:13 am
it is a quadratic equation
x^2+4x+3=24
x^2+4x-21=0
the roots are
root 1 ( -4+(16+84)^0.5)/2=(-4+10)/2=3
root 2 ( -4-(16+84)^0.5)/2=(-4-10)/2= -7
You can check replacing x either by 3 or -7
it works
x^2+4x+3=24
x^2+4x-21=0
the roots are
root 1 ( -4+(16+84)^0.5)/2=(-4+10)/2=3
root 2 ( -4-(16+84)^0.5)/2=(-4-10)/2= -7
You can check replacing x either by 3 or -7
it works
2008-03-25 12:10 am
(x+3)(x+1)=24
x² + 4x + 3 = 24
x² + 4x – 21 = 0
(x + 7)(x – 3) = 0
x = 3 or x = – 7
x² + 4x + 3 = 24
x² + 4x – 21 = 0
(x + 7)(x – 3) = 0
x = 3 or x = – 7
2008-03-25 12:09 am
(x+3)(x+1)=24
x^2+4x -21 = 0
(x+7)(x-3) = 0
x = -7 or 3
x^2+4x -21 = 0
(x+7)(x-3) = 0
x = -7 or 3
2008-03-25 12:08 am
(x+3)(x+1)=24
(x^2 + 4x + 3) = 24
x^2 + 4x - 21 = 0
(x + 7)(x - 3) = 0
x = 3 or x = -7
(x^2 + 4x + 3) = 24
x^2 + 4x - 21 = 0
(x + 7)(x - 3) = 0
x = 3 or x = -7
收錄日期: 2021-05-01 10:17:35
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