用微分解題

x^4-6x^3+3x^2+26x-24=0
Differentiae both sizes:
(4)x^(4-1)-(3)6x^(3-1)+(2)3x(2-1)+(1)26x^(1-1)-(0)24=0
4x^(3)-18x^(2)+6x^(1)+26x(0)-0=0
4x^3-18x^2+6x+26=0

2008-03-23 19:29:54 補充：
樓下果個知唔知d2次點解嫁?「D」2次係求turning point係max定min。仲用黎當2次方程咁解......你不如d夠5次，成條數變0啊笨!

2008-03-24 12:59:36 補充：
係喎.....搞錯左。
我唔知點用微分去解呢題，唯有搬番CE d數黎做
f(x)=x^4-6x^3+3x^2+26x-24
f(1)=0
(x-1)(x^3=5x^2-2x+24)
f(y)=(x^3=5x^2-2x+24)
f(3)=0
(x-1)(x-3)(x^2-2x-8)
=(x-1)(x-3)(x+2)(x-4)
x^4-6x^3+3x^2+26x-24=(x-1)(x-3)(x+2)(x-4)=0
(x-1)=0 or (x-3)=0 or (x+2)=0 or (x-4)=0
x=1 or x=3 or x=-2 or x=4

2008-03-24 13:00:36 補充：
(x^3=5x^2-2x+24)-----＞(x^3-5x^2-2x+24)