Solve by Substitution?

Substituting the value of x in the second equation,
-(4-4y)+2y=2
-4+4y+2y=2
-4+6y=2
6y=2+4=6
y=6/6
y=1
substituting the value of y in equation 1,
x=4-4(1)
x=4-4
x= 0

- (4 - 4y) + 2y = 2
- 4 + 4y + 2y = 2
6y = 6
y = 1

x = 4 - 4
x = 0

x = 0 , y = 1

x = 4 - 4y
-x = -(4 - 4y)

-x + 2y = 2
-(4 - 4y) + 2y = 2
-4 + 4y + 2y = 2
6y = 2 + 4
y = 6/6
y = 1

x = 4 - 4y
x = 4 - 4(1)
x = 4 - 4
x = 0

substiute x=4-4y in the other equqtion.
-(4-4y)+2y=2
-4+4y+2y=2
6y=2+4
=6y=6
y=1
x=0

-x+2y=2
-(4-4y)+2y=2
-4+4y+2y=2
6y=2+4
6y=6
y=6/6
y=1



-x+2y=2
-x+2(1)=2
-x=2-2
x=0

first, choose one equation and transform it so it is in terms of x or y. In this case, we use the first equation because it is in terms of x.

x=4-4y

Then, Use that equation to substitute x in the second equation.

-x+2y=2 => x=4-4y

then.

-(4-4y)+2y=2

then solve....

-4+4y+2y=2
-4+6y=2
-4+6y=(4)=2+(4)
6y=6
(6y=6)/6
y=1

then substitute y in any equation to solve for x. in this case, we use x=4-4y because it is easier to solve.

y=1
x=4-4y
x=4-4(1)
x=4-4
x=0

therefore

x=0
y=1

From (1), we have:
(4y-4) + 2y = 2
=> 6y = 6
=> y=1

=> x=0.
Substitution means you have to substitute something. In this case, replace x by 4-4y

The solutions are :
y = 1
x = 0

you just substitute x with 4-4y, so in the second one you have:
-(4-4y)+2y=2
from that, y=1
and than x=0