hkcee 2003 maths mc 42
2008-03-22 9:00 pm
In the figure, ABCD and PQRS are two rectangles of equal perimeter. If AB:BC =3:2 and PQ:QR = 4:3 ,then area of ABCD : are of PQRS =
回答 (2)
2008-03-22 9:41 pm
✔ 最佳答案
Let AB=3x and BC=2x ,PQ=4y and QR=3yABCD and PQRS are two rectangles of equal perimeter
2(AB+BC)=2(PQ+QR)
3x+2x=4y+3y
5x=7y
x/y=7/5
area of ABCD : area of PQRS
=(AB)(BC):(PQ)(QR)
=(3x)(2x):(4y)(3y)
=6x^2:12y^2
=x^2:2y^2
=1:2(y/x)^2
=1:2(5/7)^2
=1:50/49
=49:50
2008-10-09 8:19 am
收錄日期: 2021-04-26 13:56:40
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