f.5 amath

2008-03-22 8:26 am
let x be a real number
y=x^2-6x-3 find the possible range of y
if z=60/〡x^2-6x-3〡+1 find the range of possible values of z

回答 (1)

2008-03-22 7:27 pm
✔ 最佳答案
y=x^2 -6x +3

y= [x^2 - 6x + (-6/2)^2] - (-6/2)^2 +3

y = (x-3)^2 - 9 + 3

y=(x-3)^2 - 6

The possible range of y is y>=-6

if z=60/〡x^2-6x-3〡+1

The smallest value of |y| is 6

the largest values of z is 60/6+1=11

Also z>=1

The range of possible values of z is 1<=z<=11

2008-03-22 11:28:34 補充:
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2008-03-22 11:29:43 補充:
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