Math 一問....

(a)
x^2-3x-2=0
x+5+x^2-4x-7=0
y=-x^2+4x+7
y=x+5
The quadratic equation is -x^2+4x+7
(b)
x^2-3x-2=0
(x^2/3)-x-(2/3)=0
(x^2/6)-(x/2)-(1/3)=0
(x^2/6)-(x/2)+(3/2)-(11/6)=0
(x^2/6)-(x/2)+(3/2)-(11/6)=0
y=-(x/2)+(3/2)
y=-(x^2/6)+(11/6)
The quadratic equation is -(x^2/6)+(11/6)