--超趕 , 40 marks -- 各位知識朋友 , 入黎幫我手 ar !!! ( 數學F.1 ) (57)

👨🏻‍🏫 學術台數學

[匿名]

2008-03-22 4:56 am

各位知識朋友 , 入黎幫我手 ar !!!

我有兩條數學問題唔識 , 幫手解答 ar( 數學F.1 )!!!!!!!!!!!!!!! (要步驟)

( 1 ) A special tea is produced by mixing tea A,B and C in the ratio of
4 : 5 : 1 . Given that the weight of tea B in the special tea is 125 g, find
the weight of the special tea.

( 2 ) y : z = 5 : 3 , z : x = 7 : 10

更新1:

Sorry I forget type this : Question 2 is find x : y : z .

回答 (5)

Kenny

2008-03-22 5:25 am

✔ 最佳答案

( 1 ) Let the weight of the special tea be X g.
　　weight of tea B / weight of the special tea = 125/x
　　125/x = 5/(4+5+1)
　　x = 250
　　∴The weight of the special tea is 250g.

( 2 ) 你條問題係唔係求　x:y:z ?
如果係 :
　　　y : z = 5 : 3 , z : x = 7 : 10
　　　　x :　 z = 10 :　 7
　　　　 y : z = 5 : 3
　　　　x : y : z = 10×3 : 5×7 : 3×7
　　　　x : y : z = 30 : 35 : 21

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chan_firen

2008-03-22 5:34 am

1.設混合茶有x g.
125/x=5/(4+5+1)
x=250
∴混合茶有250g.

2. y:z=5:3,z:x=7:10,x:z=10:7
x:y:z=10×3:5×7:3×7
x:y:z=30:35:21

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用戶7369

2008-03-22 5:24 am

1. the weight of the special tea
= 125 x (4+5+1)/5
=250g
2. y:z=5:3 z:x=7:10
y:z=35:21 Z:x=21:30
y:z:x= 35:21:30

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hsbc65

2008-03-22 5:14 am

(1) x/5=125 x=25 10x=250 the weight of the special tea is 250g.
(2) more information.

參考: hung

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[匿名]

2008-03-22 5:13 am

1. 125g x (4+5+1) / 5 = 250 g

2. y/z = 5/3, z/x = 7/10
thus, y/z X z/x = (5x7)/(3x10)
y/x = 7/6
By substitution, 7/z = 5/3 , so z= 35/3
so x : y : z = 6 : 7 : 35/3

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收錄日期: 2021-04-29 20:24:32
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