FOIL, algebra 1. just one problem, please help?
回答 (7)
✔ 最佳答案
- 2 x² y^4 + 4 x y^5
This becomes:
-2x^2y^4 + 4xy^5
-y^3(2x^2y - 4xy^2) =
-2x^2y^4 + 4xy^5
(x+4)(x+4)(x+4) foil the 1st 2 jointly to get: x^2 +8x +sixteen then multiply that with x+4 (x+4)(x^2 +8x +sixteen) first multiply the x to the 2nd area, then the 4: x^3 +8x^2 +16x+4x^2 +32x+sixty 4 finally ends up being: x^3+12x^2+48x+sixty 4 desire this is clever
-y^3(2x^2y - 4xy^2)
= -2x^2y^4 + 4xy^5
solve it then combine like terms and youll have it its pretty easy
-y^3(2x^2y - 4xy^2) This is not FOIL, but the expansion is:
-2(x^2)(y^4)+4x(y^5)
or to put the positive term first:
4x(y^5)-2(x^2)(y^4)
收錄日期: 2021-05-01 10:15:43
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