Substitution Questions?

4b + 7c = (4 x 5) + (7 x - 2) = 20 - 14 = 6
a + b + c = 4 + 5 - 2 = 7
13 - 2a - b = 13 - 8 - 5 = 0
abc = 4 x 5 x (- 2) = (- 40)
3a - 2c + 4b = 12 + 4 + 20 = 36

= 4b + 7c
= 4(5) + 7(- 2)
= 20 - 14
= 6

= 4 + 5 - 2
= 7

= 13 - (2[4]) - 5
= 13 - 8 - 5
= 0

= 4 * 5 * (- 2)
= 20 * (- 2)
= - 40

= 3a - 2c + 4b
= 3(4) - 2(- 2) + 4(5)
= 12 + 4 + 20
= 36

1)
4b + 7c
= 4(5) + 7(-2)
= 20 + (-14)
= 20 - 14
= 6

2)
a + b + c
= 4 + 5 + (-2)
= 9 - 2
= 7

3)
13 - 2a - b
= 13 - 2(4) - 5
= 13 - 8 - 5
= 5 - 5
= 0

4)
abc
= (4)(5)(-2)
= (20)(-2)
= -40

5)
3a - 2c + 4b
= 3(4) - 2(-2) + 4(5)
= 12 - (-4) + 20
= 12 + 4 + 20
= 16 + 20
= 36

4b+7c=4x5+7x-2=20-14=6
a+b+c=4+5-2=7
13-2a-b=13-2x4-5=13-8-5=0
abc=4x5x-2=-40
3a-2c+4b=3x4+2x2+4x5=12+4+20=36

1)
4b+7c=
4(5) + 7(-2) =
20 -14 = 6

2)
a+b+c=
4 + 5 + (-2) = 7

3)
13-2a-b =
13 - 2(4) - 5 =
13 - 8 - 5 = 0

4)
abc =
4 * 5 * -2 =
20 * -2 = -40

5)
3a-2c+4b =
3(4) - 2(-2) + 4 (5) =
12 + 4 + 20 = 36

4*5 + 7*-2 = 6
4+5+ (-2) = 7
13- 2*4 - (5) = 13-8-5= 0
4*5*(-2) = -40
3*4 - 2*(-2) +4*5 = 12-(-4)+20=12+4+20=36

4(5)+7(-2) = 20 - 14 = 6
(4)+(5)+(-2) = 7
13-2(4)-(5)= 13 - 8 - 5 = 0
(4)(5)(-2)= -40
3(4)-2(-2)+4(5)= 12 + 4 + 20 = 36

Simply substitute the numbers in with the corresponding letters. If there are no addition or subtraction signs in between the number and the letter, then you need to multiply the substituted number with the other number.