How can I solve this problem? 1/3+3/4+1/2 Help?

2008-03-19 4:54 pm

回答 (10)

2008-03-19 4:58 pm
✔ 最佳答案
You have to get a common denominator.

The least common multiple between 2, 3, and 4 is 12, so let's use that. We'll turn everything into twelths.


1/3 = 4/12. 3/4 = 9/12. 1/2 = 6/12.

So, our new problem is 4/12 + 9/12 + 6/12 = 19/12.

Answer: 19/12, or, as a mixed number 1 7/12.

Hope this helps!
2008-03-19 11:57 pm
1/3 + 3/4 + 1/2
= 4/12 + 9/12 + 6/12
= 13/12 + 6/12
= 19/12
= 1 7/12
2008-03-22 5:08 pm
4/12 + 9/12 + 6/12
19/12
1 7/12
2008-03-20 12:08 am
find a similar denominator such as 12 then what you multiplied the bottom multiply the top
1/3*4/4
3/4*3/3
1/2*6/6
4/12+9/12+6/12=19/12=1 7/12
2008-03-20 12:02 am
haha .. wow.. maths i understand :)

1st u get same bottom number smalest 1 that they all go into. that would be 12

whatever u mutliply the bottom by u have to mutliply the top.

4/12 + 9/12 +6/12 = 19/12 = 1 7/12
2008-03-20 12:02 am
You need a common denominator.

Times the fractions by 4/4, 3/3 and 6/6 respectively (they all equal one so you are not altering the product).

This gives 4/12 + 9/12 + 6/12 : same denominator.

= (4+9+6)/12
=19/12 or one and seven twelfths.
2008-03-20 12:00 am
Find the common denominator of all three terms. In this case, it's 12. Rewrite the problem like this:

4/12 + 9/12 + 6/12

Now you just add up the numerators to get 19/12

If you want, you can convert that to a mixed fraction: 1 7/12
2008-03-19 11:59 pm
get the common denominator, 12

1/3=4/12
3/4=9/12
1/2=6/12

add them

get 19/12
1 7/12
2008-03-19 11:58 pm
by taking LCM i.e. 12
(4+9+6)/12
19/12
there u go
2008-03-19 11:58 pm
First get a common denominator

4/12 + 9/12 + 6/12= 19/12 which is 1 7/12.


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