maths!!!

2008-03-19 6:01 pm
1. Sam buys 500 TV game set at a total cost of $100000. If each game set is sold at a discount of 20% and he makes a profit of 20%, find
a) his total profit.
b)the selling price of each game set.
c)the marked price of each game set.
更新1:

我想問下你地點計嫁? 240分之1-20% 我唔知點計... 可唔可以比1我睇下點計?

回答 (4)

2008-03-19 6:31 pm
profit:(100000除500)x(1-20%)x20%
=200x80%x20%
=32

the selling price:(100000除500)x(1-20%)
=200x80%
=160

the marked price:100000除500
=200

2008-03-19 10:33:05 補充:
the first question is each game
becareful!
參考: me
2008-03-19 6:23 pm
a) Total Profit = $100,000 x 20% = $20,000

b)
Cost of each game set = $100,000 / 500 = $200
price = 200 / (1-20%) = $250
(p.s. this 20% means the profit percentage)

c) price = $250 / (1-20%) = $312.5
(p.s. this 20% means the discount percentage)
2008-03-19 6:19 pm
Sam buys 500 TV game set at a total cost of $100000. If each game set is sold at a discount of 20% and he makes a profit of 20%, find
a) his total profit.
b)the selling price of each game set.
c)the marked price of each game set.
a) total profit
= $100000x20%
= $20000
b) selling price
= $(100000+20000)/500
= $240
c) marked price
= $240/(1-20%)
= $300
2008-03-19 6:19 pm
a) 100000 x 0.2 = 20000

b) (100000 x 1.2) / 500 = 240

c) 240 / (1 - 0.2) = 300


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