✔ 最佳答案
One fact we should be aware of that:
Strong acids ionize COMPLETELY and weak acids ionize PARTIALLY when dissolved in water.
So for strong acids, the equation is: HA --> H+ + A-
For weak acids, the equation is: HA <--> H+ + A-
Therefore, suppose that the dissociation constant of weak acid is Ka, and original concentration of acid is C, then at equilibrium:
[H+] = [A-] = x
[HA] = C - x
Hence the degree of ionization can be approximated as x/C by assuming that C >> x.
Therefore, from the relation, we can find out that as C decreases, the degree of ionization increases for weak acid.
Hence, when a weak acid is diluted, more H+ ions are given out (in amount) and so:
For a ten-fold dilution of weak acid, the rise in pH value is less than 1 since the increase in amount of H+ ions will make the dilution effect to be less than tn-fold.
Finally, we can compare, say, by a 100-fold dilution for each of the acids and make the judgement:
Strong acid: pH rises by 2 exactly (since no more H+ ions are given out)
Weak acid: pH rises by less than 2
So at that moment, pH of the diluted strong acid = 4 while pH of the diluted weak acid < 4 and this can be verified by pH paper colour inspection.