limit

2008-03-18 2:27 pm
can anybody explain why lim(x->0) sin(x)/x = 1 to me please?

and also, the explanation for lim(x->infinity) sin2x/x= 0.

i want the proofs, explanations, and all procedures for calculating these.



in addition, how to use definition of limit to prove the limt to be exist or not exist? give me some examples in details.

回答 (1)

2008-03-18 5:59 pm
✔ 最佳答案
First question:
With reference to the diagram below:

圖片參考:http://i117.photobucket.com/albums/o61/billy_hywung/Mar08/Crazylim4.jpg

Second question: Again, it can be proved by the squeezing principle:

圖片參考:http://i117.photobucket.com/albums/o61/billy_hywung/Mar08/Crazylim5.jpg

Third question: Existence of limit can be found by verifying the existence and consistency of left-hand and right-hand limits, for example:

圖片參考:http://i117.photobucket.com/albums/o61/billy_hywung/Mar08/Crazylim6.jpg

So from the result, the limit of x - [x] does not exist for x tends to 2 since the left-hand and right hand limits are not equal.
In fact for x - [x], its limit does not exist for all x tends to any integer (either positive or negative).
Therefore, the limit of a function can be said to be not existing if:

Either left-hand or right-hand or both limits do not exist; OR
Both limits exist but they are NOT equal to each other
參考: My Maths knowledge


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