Is 15 a solution to the equation 8-x=7? Explain.?

no, here are the steps:

1) add an X to both sides. The eqtn should look like this (8=7+x)
2)Subtract a 7 from both sides. (8-7=x+7-7) ---> (1=x)

Hope it helps

8 - 15 = - 7
Thus 15 IS NOT a solution.

No, 15 cannot be the solution because if you substitute x with 15 you will get -7, not 7

a million. 8y - 35 = 3y 8y - 35 = 3y 8y-3y-35+35 =3y-3y+35 5y=35 5 y/5=35/5 y = 7 2. 6x + 3 = 2x + 11 6x-2x+3 = 2x-2x+11 4x+3-3 = 11-3 6x-2x=11-3 4x = 8 4x/4 = 8/4 x=2 3. 5y - 2 = 28 - y 5y+y-2 = 28 -y+y 6y-2 = 28 6y -2+2 = 28 +2 6y = 30 6y/6 = 30/6 y = 5 4. -18s + 6s + 2s = -9s + 15 -18s+6s+2s +9s =15 -s = 15 -s/(-a million)= 15/(-a million) s = -15 5. 7(2a - a million) = 21 14a-7 =21 14a-7+7 = 21+7 14a =28 14a/14 = 28/14 a = 2 6. 9 = 3 (5x - 2) 9 =15x-6 15x-6 = 9 15x-6+6 = 9+6 15x =15 15x/15 = 15/15 x = a million 7. 2(3 + 4m) - 9 = 40 5 6 + 8m- 9 =40 5 8m - 3 = 40 5 8m-3+3 = 40 5+3 8m = 40 8 8m/8 = 40 8/8 m = 6 8. -2 (r - a million) + 7 = 3 (r + 5) -2r + 2 +7 = 3r +15 -2r + 9 = 3r +15 -2r-3r + 9 = 3r-3r +15 -5r + 9 = 15 -5r + 9 - 9 =15 -9 -5r = 6 -5r/-5 = 6/-5 r = -6/5 9. 7 - 2x - ( - x + 7 ) = 3 + x - (x - 3) 7 - 2x + x -7 = 3 + x -x + 3 - x = 6 -x/(-a million) = 6/(-a million) x = -6 10. z - 6 (3z + 4) = 5[2z + (3z + 4) - 22] z- 18z -24 = 5(5z-18) z - 18z -24 = 25z-ninety -17z-24 = 25z - ninety -17z-25z -24 = 25z-25z-ninety -42z - 24 = -ninety -42z - 24 +24 = -ninety + 24 - 40 2 z = -sixty six -42z/(-40 2) = -sixty six/(-40 2) z = sixty six/40 2 z = (-sixty six/6)/[(-40 2)/6] z = 11/7

The answer is 1. 15 would be the answer if it were 8-x=-7.

8 - x = 7
-x = 7 - 8
-x = -1
x = -1/-1
x = 1

no ur solution is wrong hee's the solution

8-x=7
=> -x=7-8
=> -x=-1
=> x=1

therefore x=1 not 15

thats no where close.......the answer is 1

8-x=7 would mean 8- something equals 7 which is also 7 plus something equals 8 which would be 1 so
x=1