solve 4(7x+10)=3(9x-5)+20?

28x + 40 = 27x - 15 + 20
28x + 40 = 27x + 5
28x = 27x - 35
x = -35

28x + 40 = 27x - 15 + 20
x = - 15 + 20 - 40
x = - 35

First: get rid of parenthesis - use distribution > multiply the outer time period with the words in parenthesis... 4(7x) + 4(10) = 3(9x) + 3(-5) + 20 28x + 40 = 27x - 15 + 20 28x + 40 = 27x + 5 Sec: combine "like" words > subtract "40" from each and every area... 28x + 40 - 40 = 27x + 5 - 40 28x = 27x - 35 *Subtract "27x" from each and every area... 28x - 27x = 27x - 27x - 35 x = - 35

28x + 40 = (27x - 15 ) + 20
28x + 40 = 27x -15 + 20
28x + 40 = 27x + 5
28x - 27x + 40 = 5
x + 40 -5 = 0
x + 35 = 0
x = -35

verification:
----------------
4(7*(-35) + 10) = 3(9(-35)-5)+20
4((-245) + 10) = 3((-315)-5)+20
4(-235) = 3(-320)+20
(-940) = (-960)+20
(-940) = (-940)

4(7x+10) = 3(9x - 5) + 20
Expand
28x +40 = 27x - 15 + 20
28x + 40 = 27x + 5
28x + 35= 27x
35 = 27x - 28x
35 = -x
-35 = x

Always remember:
MDAS
My Dear Aunt Sally or
First: Multiplication
Then: Division
Then: Addition
Then: Subtraction
work from the parenthesis out
exponents first

4(7x + 10) = 3(9x - 5) + 20
4*7x + 4*10 = 3*9x - 3*5 + 20
28x + 40 = 27x - 15 + 20
28x - 27x = -40 - 15 + 20
x = -55 + 20
x = -35

Distribute the 4 through the parenthesis.
28x+40 = 3(9x-5)+20
Distribute the 3 through the parentesis.
28x+40 = 27x-15+20
Simplify the right side of the equation.
28x+40=27x+5
Subtract 27x from both sides to get all the variables on one side of the equation,
x+40=5
Subtract 40 from both sides to get all the constants on one side of the equation.
x=-35