equilibrium expression

2008-03-18 4:23 am
equilibrium expression


其實我想問下...

一個reaction not involving gas, 但係就involve水,

咁equilibrium expression入面使5使有水個concentration??

睇書,
Cr2O7(2-) (aq)+ H2O(l) <-------->2CrO4(2-) (aq) + 2H+(aq)
個Kc係冇[水]

但係estherification of ethanoic acid and ethanol就要計水

點解?究竟幾時先會in terms 埋of[水]?幾時5使?

麻煩大家.

回答 (1)

2008-03-18 8:21 am
✔ 最佳答案
There are two situations for water not to participate in equilibrium expression :

(1) In a heterogeneous equilibrium (it means that the components of the equilibrium are of different phases), water exists as one distinct phase. The effective concentration of water is constant. Therefore, water does not participate in the equilibrium expression.

(2) In an dilute aqueous solution, water is the solvent and is in extremely large excess. When reaction occurs in the dilute solution, the change in concentration of the water solvent is negligible. Therefore, the concentration of water is nearly constant, and water thus does not participate in the equilibrium expression.

The esterification of ethanoic acid and ethanol :
CH3COOH(l) + CH3CH2OH(l) = CH3COOCH2CH3(l) + H2O(l)
At equilibrium, the four components mixed together and form a homogeneous layer. Since water is not in large excess and is miscible in the reaction mixture, water should participate in the equilibrium expression.


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