1. Prove the following inequality when a>0 and b>0. Then state the conditions for which the LHS equals the RHS.
(a+b)(1/a + 1/b ) >= 4
proof of inequalities-- urgent (20 points)
2008-03-15 10:38 pm
回答 (2)
2008-03-15 10:53 pm
✔ 最佳答案
As follows~~~As follows~~~
圖片參考：http://i182.photobucket.com/albums/x4/A_Hepburn_1990/A_Hepburn09Mar151453.jpg?t=1205564012
參考: Myself~~~
2008-03-15 11:07 pm
By Cauchy-Schwarz;s Inequality
(A＋B)(1/A＋1/B)＞＝square of【開方A(1/開方A)＋開方B(1/開方B)】
(A＋B)(1/A＋1/B)＞=square of (1＋1)=4
The inequality holds iff A=B
(A＋B)(1/A＋1/B)＞＝square of【開方A(1/開方A)＋開方B(1/開方B)】
(A＋B)(1/A＋1/B)＞=square of (1＋1)=4
The inequality holds iff A=B
參考: 自己math底
收錄日期: 2021-04-13 15:17:30
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