What is the result when you divide (-32x^3+24x^2-16x) by -4x?
回答 (8)
2008-03-14 5:50 pm
✔ 最佳答案
Divide -4x by each term(-32x^3 / -4x) + (24x^2 / -4x) - (16x / -4x)
= 8x^2 + -6x + 4
2008-03-15 12:50 am
32 x ³ - 24 x ² + 16 x
-----------------------
4 x
8 x ² - 6 x + 4
-----------------------
4 x
8 x ² - 6 x + 4
2008-03-15 12:50 am
(-32x³ + 24x² - 16x) / (-4x)
8x² - 6x + 4
8x² - 6x + 4
2008-03-15 12:52 am
(-32x^3 + 24x^2 - 16x)/-4x
= -4x(8x^2 - 6x + 4)/-4x
= (8x^2 - 6x + 4)/1
= 8x^2 - 6x + 4
= 2(4x^2 - 3x + 2)
= -4x(8x^2 - 6x + 4)/-4x
= (8x^2 - 6x + 4)/1
= 8x^2 - 6x + 4
= 2(4x^2 - 3x + 2)
2008-03-15 12:56 am
-32x^3/-4x=8x^2
24x^2/-4x=-6x
-16x/-4x=4
8x^2 - 6x + 4
24x^2/-4x=-6x
-16x/-4x=4
8x^2 - 6x + 4
2008-03-15 12:55 am
-32x^3+24x^2-16x) by -4x
means,
(-32x^3/-4x )+ (24x^2/-4x) - (16x/-4x)
Simplify each term,
(8x^2) + (-6x) - (-4)
8x^2 - 6x + 4
means,
(-32x^3/-4x )+ (24x^2/-4x) - (16x/-4x)
Simplify each term,
(8x^2) + (-6x) - (-4)
8x^2 - 6x + 4
2008-03-15 12:54 am
(-32x^3+24x^2-16x) / -4x
easiest thing is to factor out a -4x from the numerator first
(-32x³+24x²-16x)
-4x(8x²-6x+4)
so
(-32x³+24x²-16x)
-----
-4x
becomes
-4x(8x²-6x+4)
------------------
-4x
the -4x's cancel and you're left with
8x²-6x+4
easiest thing is to factor out a -4x from the numerator first
(-32x³+24x²-16x)
-4x(8x²-6x+4)
so
(-32x³+24x²-16x)
-----
-4x
becomes
-4x(8x²-6x+4)
------------------
-4x
the -4x's cancel and you're left with
8x²-6x+4
2008-03-15 12:50 am
8x^2 - 6x +4
收錄日期: 2021-05-01 10:13:03
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