Solve this inequality: 3b – 7 < 32.?

3b < 39
b < 13
OPTION D

3b-7 < 32
3b-7+7 < 32+7
3b < 39
b < 13
(D)

adding 7 to both sides gives
3b<39

divide both sides by 3
b<13

b < 13

3b - 7 < 32
3b < 32 + 7
3b < 39
b < 39/3
b < 13
(answer D)

3b 7 32

i won't be able to help with the 1st 3. listed here are those i comprehend. 32. 2 + 2k [<_] 8 (Subtract 2 from the two factors) 2k [<_] 6 (Divide 2 from the two factors) ok [<_] 3 32. 2r - 9 [>_] -6 (upload 9 to the two factors) 2r [>_] 3 (Divide 2 from the two factors) r [>_] 3/2 or a million a million/2 34. -4k + 5 [<_] 21 (Subtract 5 from the two factors) -4k [<_] sixteen (Dived -4 from the two factors and turn sign) ok [>_] 4 35.2(4y - 5) < -10 (Multiply 2 into 4y and -5) 8y -10 < -10 (upload ten to the two factors) 8y < 0 (Divide 8 from the two factors) y < 0/8 that's undefined. 36. 4(3b - 5) < -31 + 12b (Multiply 4 to 3b and -5) 12b -20 < -31 +12b (upload 31 to the two factors) 12b +11 < 12b (Subtract 12b from the two factors) 11 < 24b (Divide 24 from the two factors) b > .172 or .172 < b 37.26 + 6b [>_] 2(3b + 4) (Multiply 2 to 3b and four) 26 +6b [>_] 6b +8 (Subtract 8 from the two factors) 18 +6b [>_] 6b (Subtract 6b from the two factors) 18 [>_] 0 36. top could desire to be sixty 4 inches. Width = 36. (w2) 36 x 2 = 72 (p=200) a hundred - 72 = 128 (128 = h2) 128 divided by using 2 = sixty 4. examine: P=(w2) + (h2) P=(36 x 2) + (sixty 4 x 2) P=(72) + (128) P=200 (: