Solve each of the equations and show all steps.?

-2x + 8 = -4(x - 3)
-2x+8 =-4x-12 (remove bracket)
-2x+4x = -12+-8
2x = -20
x= -10

3 - (x + 7) = 10
3-x-7=10
x= 3-7-10
x= 14

2a2 a=5
2*5*2 = 40

3(x-5)+2x
3x-15+2x
5x-15

2(3-5)
6-10
-4

x+y=7
2x-3y=-6
x = 7-y
2(7-y)-3y =-6
14-2y-3y = -6
14-5y = -6
14+6 = 5y
y = 20/5
y = 4
x+y=7
x+4 = 7
x = 7-4
x=3

-12+c=19
c = 19+12
c = 31

Question 1
- 2x + 8 = - 4x + 12
2x = 4
x = 2

Question 2
3 - x - 7 = 10
- x - 4 = 10
x = - 14

Question 3
2 (5²) = 2 x 25 = 50

Question 4
| 3 - 6 | = | - 3 | = 3

Question 5
3x - 15 + 2x
5x - 15

Question 6
2 (- 2) = (- 4)

Question 7
3x + 3y = 21
2x - 3y = - 6-------ADD

5x = 15
x = 3

3 + y = 7
y = 4

x = 3 , y = 4

Question 8
c = 31

a.) x/5 + 2x/15=8 once you spot fraction including yet another fraction and equating to a definite quantity, continually start up finding on the backside of the two fractions. so 5 and 15. How do you're making them the comparable quantity? you could't cause them to the two 5 by way of fact which you could't divide 15 by 3; that doesn't make any sense. What you need to do is multiply 5 by 3 and cause them to the two 15. so x/15 + 2x/15 =8. yet: what did we do with the 5? We in simple terms expanded 5 by 3 to make it 15 acceptable? consequently, u ought to multiply the suitable by 3 additionally. so now: 3x/15 + 2x/15 = 8. then, 5x/15= 8. we wanna bypass away the x on my own, so we ought to be sure what quantity x is. so multiply 15 the two sides; then, you need to do away with the 15 on the backside. 5x= a hundred and twenty divide 5 the two sides. a hundred and twenty/5=24. answer: 24 hopefully you need to do B. its great uncomplicated. i will practice you as we talk by way of fact that i taught u partly A intimately. 2k/5 - 3k/4 = 10 8k/20 - 15k/20 = 10 -7k/20 = 10 -7k = 2 hundred ok= - 2 hundred/7 For area b, once you're at a loss for words why the backside is 20, the explanation is that the two considered one of them are no longer multiplyable, no remember if it fairly is even a technical term. you could't divide remember. so which you could't multiply 5 by some thing to make 4. comparable element for 4. So, throughout this form of undertaking, you in simple terms multiply. 5x4= 20. now it fairly works for the two 5 and four. desire i helped!

just remember to open up the bracket first

is very simple

8-2x = -4x + 12
8-2x = 12
2x = 4
2x/2 = 4/2
x = 2

just use this method for all the question

1)
-2x + 8 = -4(x - 3)
-2x + 8 = -4x + 12
-2x + 4x = -8 + 12
2x = 4
x = 4/2
x = 2

2)
3 - (x + 7) = 10
3 - x - 7 = 10
-x = 10 - 3 + 7
-x = 7 + 7
-x = 14
x = 14/-1
x = -14

3)
2a^2
= 2(5^2)
= 2(25)
= 50

4)
| 3 - 6 |
= 3

5)
3(x - 5) + 2x
= 3x - 15 + 2x
= 3x + 2x - 15
= 5x - 15
= 5(x - 3)

6)
2(3 - 5)
= 6 - 10
= -4

7)
x + y = 7
x = 7 - y
2x = 2(7 - y)

2(7 - y) - 3y = -6
14 - 2y - 3y = -6
14 - 5y = -6
-5y = -6 - 14
-5y = -20
y = -20/-5
y = 20/5
y = 4

x + y = 7
x + 4 = 7
x = 7 - 4
x = 3

8)
-12 + c = 19
c = 19 + 12
c = 31