(答案~列識~點計出來)20點

Q.1
4x3.14 cm
=12.56 cm

Q.2
12x3.14x1/2+12 cm
=30.84 cm

Q.3
10x2x3.14x3/4+10+10 cm
=67.1 cm

Q.4
15x2x3.14x1/4+15+15 cm
=53.55 cm

Q.5
(2+16+2)x3.14x1/2+16x3.14x1/2+2+2 cm
=60.52 cm

Q.6
6x3.14x1/2x2+12+12 cm
=42.84 cm

Q.7
14x2x3.14x1/4x2 cm
=43.96 cm

Q.8
(2+18+2)x3.14x1/2+18x3.14x1/2+2+2 cm
=66.8 cm

Q.9
30x3.14x1/2+15x2x3.14x1/4x2 cm
=94.2 cm

d 為直徑 = 2r　r 為半徑　*為角度符號
1. 周界 :
πd
= ( 3.14 )( 4 )
= 12.56 cm
2. 周界 :
( πd )/2 + 12
= ( 3.14 x 12 )/2 + 12
= 30.84 cm
3. 如兩直線之間的角度 = 90*
周界 :
2πr x θ/360* + 2 x 10
= 2( 3.14 )( 10 ) x 270/360 + 20
= 67.1 cm
4. 周界 :
2πr x θ/360* + 2 x 15
= 2( 3.14 )( 15 ) x 90*/360* + 30
= 53.55 cm
5. 此題中 d1 為較大半圓形的直徑　d2 為較小半圓形的直徑
周界 :
( πd1 )/2 + ( πd2 )/2 + 2 x 2
= [ 3.14( 16 + 2 + 2 ) ]/2 + ( 3.14 x 16 )/2 + 4
= 60.52 cm
6. 周界 :
( πd )/2 x 2 + 2 x 12
= ( 3.14 x 6 ) + 24
= 42.84cm
7. 周界 :
2πr x θ/360* x 2
= 2( 3.14 x 14 ) x 90*/180*
= 43.96 cm
8. 此題中 d1 為較大半圓形的直徑　d2 為較小半圓形的直徑
( πd1 )/2 + ( πd2 )/2 + 2 x 2
= [ 3.14( 18 + 2 + 2 ) ]/2 + ( 3.14 x 18 )/2 + 4
= 66.8 cm
9. 周界 :
( πd )/2 + ( πd ) x θ/360* x 2
= ( 3.14 x 30 )/2 + ( 3.14 x 30 ) x 90*/180*
= 94.2 cm