find the value of x corr. to 3 sig fig
更新1:
下 ........ 唔係呀...........
更新2:
靠估？...
更新3:
joyce 計錯數喎... 點解可以全部一齊 log 嫁= = log(a+b)=/= log a + log b!
中四數學難題
回答 (2)
2008-03-12 10:30 pm
✔ 最佳答案
Consider the following tablex
6^x
11^2x
6^x+11^2x-199
1
6
121
-72
2
36
14641
14478
1.5
14.69694
1331
1146.696938
1.25
9.390507
401.3116
211.7021071
1.125
7.5062
220.3604
28.86659514
1.0625
6.710976
163.2899
-28.99907376
1.09375
7.09746
189.6909
-2.211639637
1.109375
7.298969
204.4514
12.75033712
1.101563
7.197509
196.9329
5.130401713
1.097656
7.147309
193.278
1.425289902
1.095703
7.122341
191.476
-0.401618264
The value of x is between 1.095703 and 1.097656
x = 1.10 corr. to 3 sig. fig.
2008-03-20 12:54 am
Ans :
6^x+11^(2x)=199
x(log6)+(2x)(log11)=log199
x(log6+2log11)=log199
x=log199/(log6+2log11)
x=0.804
6^x+11^(2x)=199
x(log6)+(2x)(log11)=log199
x(log6+2log11)=log199
x=log199/(log6+2log11)
x=0.804
收錄日期: 2021-04-20 23:34:04
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