Factor: x^2 + 6x + 8?

2008-03-11 7:47 am
a. (x + 2) (x + 4)
b. (x + 1) (x + 8)
c. (x - 2) (x - 4)
d. (x - 1) (x - 8)

回答 (10)

2008-03-11 7:51 am
✔ 最佳答案
A) (x + 2)(x + 4)

You can confirm this by using FOIL to multiply it out:

x² + 4x + 2x + 8
= x² + 6x + 8

Answer:
A) (x + 2)(x + 4)
2008-03-11 11:34 am
(x + 2)(x + 4)
OPTION a.
2008-03-11 7:50 am
a for sure!
2008-03-11 7:53 am
x^2 + 6x + 8
= x^2 + (4 +2)x + 8
= x^2 + 4x +2x + 8
= x(x + 4) +2(x + 4)
= (x + 4)(x + 2)
a is answer.
2016-05-28 3:05 pm
First you have to make the equation equal zero. x^2 - 6x + 8 = 0 Then you have to factor by the decomposition method. To do this you have to find the factors of 8 that add up to -6. They are -2 and -4. Now you have to write two sets of brackets with an x in each one and -2 in one and -4 in the other. (x - 2)(x - 4) = 0 Now take each factor and solve for the variable. x - 2 = 0 x = 2 x - 4 = 0 x = 4 Therefore the solutions are 2 and 4.
2008-03-11 9:01 am
it is the first one!
a.(x + 2) (x + 4)
2008-03-11 7:58 am
If x^2+6x+8=(x+a)(x+b), then (a+b)=6 and ab=8
Checking the answers shows that 2+4=6 and 2x4=8. so answer a is correct.
2008-03-11 7:54 am
---delta = b² - 4*a*c
---delta = 6² - 4*(1)*8
---delta = 4
x1 = (- b + raiz de delta)/2a -> x1 = ( - 6 + 2)/2*1 -> x1 = - 2
x2 = (- b - raiz de delta)/2a -> x2 = ( - 6 - 2)/2*1 -> x2 = - 4.

---Then the equation can be write:
(x - x1)*(x - x2) = (x - (-2))*(x - (-4)) = (x + 2)*(x + 4) -> a).
2008-03-11 12:54 pm
x^2 + 6x + 8
= x^2 + 4x + 2x + 8
= (x + 4)(x + 2) or (x + 2)(x + 4)
(answer a)
2008-03-11 7:54 am
x^2 + 6x+ 8
= x^2 + 4x + 2x + 8
= x(x+4) + 2(x + 4)
= (x + 2) (x + 4)

therefore the answer is a. (x+2) (x + 4)


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