Please solve this problem for me:2(y -1/2) = 4(y -1/4) + y Thanks?

2y - 1 = 4y - 1 + y
0 = 3y
y = 0

2(y -1/2) = 4(y -1/4) + y
2y-1=4y-1+y
-1+1=4y+y-2y
0=y
y=0

2y-1=4y-1+y
-2y-y=0
y=0

2(y-1/2)=4(y-1/4)+y
open the brackets 2y -2/2=4y-4/4+y
2/2 -they will cancel and so will 4/4
so 2y -1 = 4y-1+y
put the ys on one side
-1+1=4y-2y +y
0=3y
y=0

hope i solved it right

2(y - 1/2) = 4(y - 1/4) + y
2y - 2/2 = 4y - 4/4 + y
2y - 1 = 4y - 1 + y
2y - 4y - y = 1 - 1
-2y - y = 0
-3y = 0
y = 0/-3
y = 0

2y-1=4y-1
2y=4y
y=2y
y=0