唔該解釋埋同計埋出黎比我ar-__-'
(x²-x-6/3-3x)÷(x-3/x²-2x+1)
[3y-(12y²-4y-1/2y-1)]×(4y²-4y+1/6y²-y-1)
(6x-3y/10x²+xy-3y²)×(5x²+8xy+3y²)
唔該哂..
F.2數Factorization(因式分解)急!!
2008-03-10 3:19 am
回答 (1)
2008-03-10 5:58 am
✔ 最佳答案
(x²-x-6/3-3x)÷(x-3/x²-2x+1)= (x-3)(x+2)/3(1-x) X (1-x)(1-x)/(x-3)
=(x+2)(1-x)/3
[3y-(12y²-4y-1/2y-1)]×(4y²-4y+1/6y²-y-1)
=[3y-(6y+1)(2y-1)/(2y-1))] X (2y-1)(2y-1)/(3y+1)(2y-1)
=-(3y+1)(2y-1)/(3y+1)
=1-2y
(6x-3y/10x²+xy-3y²)×(5x²+8xy+3y²)
=3(2x-y)/(5x+3)(2x-y) X (5x+3y)(x+y)
=3(x+y)
收錄日期: 2021-04-30 22:10:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080309000051KK02882