how do you simplify this equation? (x^-2)^-1?

Rule
(x^a)^b = x ^(ab)

x^(-2)^(-1) = x^2 = x²

x^2

i dont think its possible, ive tried everything i know

x^2 is the answer

(x^-2)^-1
= 1/(x^-2)
= 1/(1/x^2)
= 1 ÷ 1/x^2
= 1 * x^2/1
= x^2/1
= x^2

When raising a power to a power, multiply the powers:

(x^-2)^-1 = x^[(-2)*(-1)] = x^2

The negative exponent triggers a reciprocal.

1/(x^2 - 2)

This is equal to

[ 1 / (x^2) ] ^-1

Then you just take the recipricol of that.

The ans is x^2

Hope that was clear.

The answer is x^2. I am 100 percent sure. This is why: when an exponent is raised to another power, they multiply, the formula is this: (x^m)^n = x^mn. So (x^-2)^-1 = x^(-2)(-1)= x^2.