Factor by grouping xy + 2x + 3y + 6?

x ( y + 2 ) + 3 (y + 2 )
( y + 2 ) ( x + 3 )

xy + 2x + 3y + 6
x(y + 2) + 3(y + 2)
(x + 3)(y + 2)

Technically, none of your answers are correct. C is "right", but not completely factored.

xy + 2x + 3y + 6 Group them like this
(xy + 2x) + (3y + 6) Factor out what's common in each pair
x(y+2) + 3(y + 2) C is a correct answer but it isn't factored completely. There is still a (y + 2) in common.

(y + 2)(x + 3)

It's letter c.

You factor x from xy+2x and a 3 from 3y+6.

Hope this helps!

x(y+2)+3(y+2)=(y+2)(x+3)
so, the answer is c

xy + 2x + 3y + 6
= (x + 3)(y + 2) or x(y + 2) + 3(y + 2)
(answer c.)

It would be C. because from the first group, you can take out an x and get x(y+2) from the second you could take out a three 3(y+2)

xy + 2x + 3y + 6
= x (y+2) + 3 (y+2)
= (x+3) (y+2)

Answer is C.
But it still could be factored down some more.

(x+3)(y+2) basic algebra man

I Believe it is C.