a. (x + 2) (y + 3)
b. x + 3) (y + 3)
c. x (y + 2) + 3 (y + 2)
d. this problem cannot be factored.
Factor by grouping xy + 2x + 3y + 6?
2008-03-09 3:23 am
回答 (13)
2008-03-10 8:53 am
✔ 最佳答案
x ( y + 2 ) + 3 (y + 2 )( y + 2 ) ( x + 3 )
2008-03-09 3:26 am
xy + 2x + 3y + 6
x(y + 2) + 3(y + 2)
(x + 3)(y + 2)
Technically, none of your answers are correct. C is "right", but not completely factored.
x(y + 2) + 3(y + 2)
(x + 3)(y + 2)
Technically, none of your answers are correct. C is "right", but not completely factored.
2008-03-09 3:33 am
xy + 2x + 3y + 6 Group them like this
(xy + 2x) + (3y + 6) Factor out what's common in each pair
x(y+2) + 3(y + 2) C is a correct answer but it isn't factored completely. There is still a (y + 2) in common.
(y + 2)(x + 3)
(xy + 2x) + (3y + 6) Factor out what's common in each pair
x(y+2) + 3(y + 2) C is a correct answer but it isn't factored completely. There is still a (y + 2) in common.
(y + 2)(x + 3)
2008-03-09 3:28 am
It's letter c.
You factor x from xy+2x and a 3 from 3y+6.
Hope this helps!
You factor x from xy+2x and a 3 from 3y+6.
Hope this helps!
2008-03-09 3:27 am
x(y+2)+3(y+2)=(y+2)(x+3)
so, the answer is c
so, the answer is c
2008-03-09 9:06 am
xy + 2x + 3y + 6
= (x + 3)(y + 2) or x(y + 2) + 3(y + 2)
(answer c.)
= (x + 3)(y + 2) or x(y + 2) + 3(y + 2)
(answer c.)
2008-03-09 3:32 am
It would be C. because from the first group, you can take out an x and get x(y+2) from the second you could take out a three 3(y+2)
2008-03-09 3:30 am
xy + 2x + 3y + 6
= x (y+2) + 3 (y+2)
= (x+3) (y+2)
Answer is C.
But it still could be factored down some more.
= x (y+2) + 3 (y+2)
= (x+3) (y+2)
Answer is C.
But it still could be factored down some more.
2008-03-09 3:28 am
(x+3)(y+2) basic algebra man
2008-03-09 3:27 am
I Believe it is C.
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