X^ (-2/3) = 9 how to find the x? math?

x^(-2/3) = 9
Raise each side to the power of (-3/2) :
x = 9^(-3/2)
= 1 / 9^(3/2)
= 1 / [9^(1/2)]^3
= 1 / 3^3
= 1/27

1 / x^(2/3) = 9
1 / 9 = x^(2/3)
(1 / 9)^(3/2) = x
(1 / 3²)^(3/2) = x
1 / 3³ = x
x = 1 / 27

x^(-2/3) = 9
1/x^(2/3) = 9
1/9 = x^(2/3)
Get the square root:
1/3 = x^(1/3)
Get the cube:
1/27 = x

x^(-2/3) = 9

Cube both sides:

x^(-2) = 729

Restate:

1/x² = 729

Invert:

x² = 1/729

Take square root:

x = √(1/729)

Simplify:

x = 1/27

x^(-2/3) = 9
3√(x^-2) = 9
3√(1/x^2) = 9
1/x^2 = 9^3
1/x^2 = 729
1 = 729x^2
729x^2 - 1 = 0
(27x + 1)(27x - 1) = 0

27x + 1 = 0
27x = -1
x = -1/27

27x - 1 = 0
27x = 1
x = 1/27

log(to base x)9 = -2/3

log(to base10)9/log(to base 10)x = -2/3

log(to base 10)x = log(tobase10)9/(-2/3)

= -1.431

x = 10^-1.431

= 3.7 * 10^-2

X^(-2/3)=1/{X^(2/3)}=9

=>X^2/3=1/9

=>X=(1/9)^3/2

=>X=(1/2)^3

=>X=1/8

Multiply the two aspects through -9 3x^2 + x = 2 3x^2 + x - 2 = 0 Use the quadratic formula: ax^2 + bx + c = 0, then x = (-b +/- sqrt(b^2 - 4ac)) / (2a) a = 3 b = a million c = -2 x = (-a million +/- sqrt(a million^2 - 4 * 3 * (-2))) / (2 * 3) x = (-a million +/- sqrt(a million + 24)) / 6 x = (-a million +/- sqrt(25)) / 6 x = (-a million +/- 5) / 6 x = -6/6 , 4/6 x = -a million , 2/3