3n2+3n-90 ?
回答 (12)
2008-03-08 6:48 am
✔ 最佳答案
3n² + 3n - 90= 3(n² + n - 30)
= 3(n² - 5n + 6n - 30)
= 3(n(n-5)+6(n-5))
= 3(n+6)(n-5)
2008-03-08 6:48 am
3n² + 3n - 90
3(n² + n - 30)
3(n + 6)(n - 5)
3(n² + n - 30)
3(n + 6)(n - 5)
2008-03-08 6:48 am
3(n^2+n-30 )====> 3(n+6)(n-5)
2008-03-09 11:07 am
3 ( n ² + n - 30 )
3 ( n + 6 ) ( n - 5 )
3 ( n + 6 ) ( n - 5 )
2016-12-01 9:38 am
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2008-03-08 6:56 am
hi!
3n^2 + 3n - 90
factor out 3 first:
3(n^2 + n - 30)
factor (n^2 + n - 30) and multiply it with 3
3(n - 6)(n + 5)
i hope this helps
=)
3n^2 + 3n - 90
factor out 3 first:
3(n^2 + n - 30)
factor (n^2 + n - 30) and multiply it with 3
3(n - 6)(n + 5)
i hope this helps
=)
2008-03-08 6:51 am
First divide the 3 out of each term:
=3(n^2+n-30)
Then do your usual factoring method (what two numbers multiply to -30 and add to 1), which are 6 and -5:
=3(n+6)(n-5)
PS- n^2 means n squared :)
=3(n^2+n-30)
Then do your usual factoring method (what two numbers multiply to -30 and add to 1), which are 6 and -5:
=3(n+6)(n-5)
PS- n^2 means n squared :)
2008-03-08 6:51 am
Theres a trick for these:
Take 3 from the n^2 and the -90 and multiply to get -270.
Now you need two numbers whose product is -270 and
whose sum is equal to 3. That would be 18 and -15, since
18 + -15 = 3 and 18 x -15 = -270. Rewrite expression as:
3n^2 + 18n - 15n - 90 and factor:
3n(n + 6) -15(n + 6) = (3n - 15)(n + 6) = 3(n - 5)(n + 6).
If you can factor, this method always works.
Take 3 from the n^2 and the -90 and multiply to get -270.
Now you need two numbers whose product is -270 and
whose sum is equal to 3. That would be 18 and -15, since
18 + -15 = 3 and 18 x -15 = -270. Rewrite expression as:
3n^2 + 18n - 15n - 90 and factor:
3n(n + 6) -15(n + 6) = (3n - 15)(n + 6) = 3(n - 5)(n + 6).
If you can factor, this method always works.
2008-03-08 6:49 am
3n^2 + 3n - 90
=3(n+6)(n-5)
how did some of my above authors got the 2 in superscript
=3(n+6)(n-5)
how did some of my above authors got the 2 in superscript
2008-03-08 7:54 am
3n^2 + 3n - 90
= 3(n^2 + n - 30)
= 3(n + 6)(n - 5)
= 3(n^2 + n - 30)
= 3(n + 6)(n - 5)
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