how would you go about solving this....
add together:
1/x + 2x
algabraic fractions?
2008-03-07 5:23 pm
回答 (7)
2008-03-07 5:29 pm
✔ 最佳答案
1. Find Common DenominatorThe common denominator is x..
the first term (1/x) has an x in the denominator..so you can just leave it alone
The second term (2x) is missing an x in the denominator..so you have to multiply it by x
1/x + 2x = (2x^2 + 1)/ x
2008-03-08 1:29 am
= 1/x + 2x
= 1/x + 2x²/x
= (2x² + 1)/x
Answer: (2x² + 1)/x
= 1/x + 2x²/x
= (2x² + 1)/x
Answer: (2x² + 1)/x
2008-03-08 1:28 am
1/x + 2x^2/x
= (1 + 2(x^2))/x
= (1 + 2(x^2))/x
2008-03-08 1:26 am
1/x + 2x
1/x + 2x^2/x
(1+2x^2)/x
1/x + 2x^2/x
(1+2x^2)/x
2008-03-08 1:26 am
1/x + 2x
1/x + 2x^2/x
(1+2x^2)/x
1/x + 2x^2/x
(1+2x^2)/x
2008-03-08 1:26 am
common denominator
1/x + 2x^2/x = (2x^2 + 1)/x
1/x + 2x^2/x = (2x^2 + 1)/x
2008-03-08 1:25 am
1/x + 2x
= 1/x + 2x^2/x
= (1 + 2x^2)/x
= 1/x + 2x^2/x
= (1 + 2x^2)/x
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