更新1:
Please show me how you get your answer so I can know how to do it.
How do you solve: 5y=40y+84?
2008-03-07 4:30 pm
I'm doing systematic equations. I made it to this point but when I try to get y by itself I keep getting the wrong answer. I'm no good in math. Help!
回答 (18)
2008-03-10 8:43 am
✔ 最佳答案
5y - 84 = 40y- 84 = 35y
y = - 84 / 35
2008-03-07 4:40 pm
5y = 40y + 84
35y = - 84
y = - 2 2/5 or - 2.4
Answer: - 2 2/5 or - 2.4
Proof:
5(- 2.4) = 40(- 2.4) + 84
- 12 = - 96 + 84
- 12 = - 12
35y = - 84
y = - 2 2/5 or - 2.4
Answer: - 2 2/5 or - 2.4
Proof:
5(- 2.4) = 40(- 2.4) + 84
- 12 = - 96 + 84
- 12 = - 12
2008-03-07 4:48 pm
It's pretty easy don't worry.
5y = 40y + 84 subtract 40 to both 5y and 40y so 40y
-40 = -40 - 40 would cross out!
so now you have the problem shown below. now have to divide by -35.
- 35y = 84
------- = -----
- 35 -35
the - 35 cross out! and left with y.
So 84 divided by -35 = - 2.4
The answer is (y = - 2.4) Glad to help!
5y = 40y + 84 subtract 40 to both 5y and 40y so 40y
-40 = -40 - 40 would cross out!
so now you have the problem shown below. now have to divide by -35.
- 35y = 84
------- = -----
- 35 -35
the - 35 cross out! and left with y.
So 84 divided by -35 = - 2.4
The answer is (y = - 2.4) Glad to help!
參考: From math teacher.
2008-03-07 4:48 pm
5y-40y=84
-35y=84
-35y/-35=84/-35
y=-2.4
-35y=84
-35y/-35=84/-35
y=-2.4
2008-03-07 4:42 pm
Solution:
5y = 40y + 84
Therefore, rewriting we get 5y - 40y = 84
-35y = 84
y = 84 / (-35)
y = -2.4
5y = 40y + 84
Therefore, rewriting we get 5y - 40y = 84
-35y = 84
y = 84 / (-35)
y = -2.4
2008-03-07 4:36 pm
5y = 40y + 84
First, make sure the values with the variables are on the same side of the equation
- Subtract 40y from both sides to get:
-35y = 84
Now, isolate the y-variable.
- Divide each side by -35.
y= 84/-35 or -2.4
First, make sure the values with the variables are on the same side of the equation
- Subtract 40y from both sides to get:
-35y = 84
Now, isolate the y-variable.
- Divide each side by -35.
y= 84/-35 or -2.4
2008-03-07 4:35 pm
5y = 40y + 84
5y - 40y = 84
-35y = 84
y = 84/-35
y = 12/-5
y = -2 2/5 (-2.4)
5y - 40y = 84
-35y = 84
y = 84/-35
y = 12/-5
y = -2 2/5 (-2.4)
2008-03-07 4:35 pm
5y=40y+84
5y-40y=84
-35y=84
y=84/(-35)
y=-2.4
5y-40y=84
-35y=84
y=84/(-35)
y=-2.4
2008-03-07 4:34 pm
40y-5y=84
-35y=84
35/35=84/-35
y=-2.4
-35y=84
35/35=84/-35
y=-2.4
2008-03-07 4:37 pm
5y-40y=84
-35y= 84
y= -84/35= -12/5
-35y= 84
y= -84/35= -12/5
2008-03-07 4:36 pm
That's actually::
5y-40y=84
=> -35y=84
=> -y=84/35
=> y=-84/35
5y-40y=84
=> -35y=84
=> -y=84/35
=> y=-84/35
2008-03-07 4:34 pm
Subtract 40y on both sides of the equation,
5y-40y=40y-40y+84
-35y=84
Divide both sides by -35,
y=-35/84 OR -0.417
5y-40y=40y-40y+84
-35y=84
Divide both sides by -35,
y=-35/84 OR -0.417
2008-03-07 4:34 pm
5y=40y+84
get all the y's on the same side
5y-40y=84
-35y=84
y=-84/35
get all the y's on the same side
5y-40y=84
-35y=84
y=-84/35
2008-03-07 4:34 pm
Hint
5y - 40y=84
-35y = 84
5y - 40y=84
-35y = 84
2008-03-07 4:34 pm
5y-40y = 84
-35y = 84
-y = 84/35
-y = 2,4
y = -2,4
-35y = 84
-y = 84/35
-y = 2,4
y = -2,4
2008-03-07 4:33 pm
5y=40y+84
subtract 40y:
-35y=84
y=-12/5
subtract 40y:
-35y=84
y=-12/5
2008-03-07 4:33 pm
-35y = 84
y = -84/35
y = -84/35
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