How do you solve 2 (x + 9 ) + 2x = 38?

2x + 18 + 2x =38
4x = 20
x = 5

2x + 18 + 2x = 38
4x + 18 = 38
4x = 38- 18
4x = 20
x =5


p/s:do you know that the number inside of the brackets hav to be times with the number outside of the bracket

*2(y + 9)..means...2 x y.=2y.and 2 x 9.=18..so the overall answer for this example is ..= 2y + 18

2 (x + 9) + 2x = 38
2x + 18 + 2x = 38
2x + 2x = 38 -18
(4x = 20) 1/4 => multiply d whole eqn to 1/4 to cancel d 4 in 4x

x = 5

The solve of this eq. is :
2(x+9)+2x=38
2x + 18 + 2x=38
4x= 38-18
4x=20
x=20/4
x=5

2(x + 9) + 2x = 38
2x + 18 + 2x = 38
2x + 2x = 38 - 18
4x = 20
x = 20/4
x = 5

5

2 (x + 9 ) + 2x = 38
2x+18+2x=38
4x=38-18
4x=20
x=20/4
x=5

answer is 5

solution:
2(x+9) + 2x = 38
2x+18+2x = 38
4x + 18 = 38
4x = 38 - 18
4x = 20 divide by 4 to find value of x
x = 5

2x + 18 + 2x = 38
4x + 18 = 38
4x + 18 - 18 = 38 - 18
4x = 20
x = 5

2(x + 9) + 2x = 38

2x + 18 + 2x = 38

2x + 2x = 38 - 18

4x = 20

x = 5