Factor 25-(x^2+4x+4)?

2008-03-07 8:35 am

回答 (9)

2008-03-08 8:10 pm
✔ 最佳答案
25 - (x + 2)²
[ 5 - (x + 2) ] [ 5 + (x + 2) ]
( 3 - x ) ( 7 + x )
2008-03-07 4:42 pm
25-(x^2+4x+4)
= 25-x^2-4x-4
= -x^2 - 4x +21
= -(x^2 + 4x -21)
= -(x +7)(x - 3) or =(x + 7)(3 - x)
2008-03-07 4:42 pm
25 - (x^2 + 4x + 4) = 25 - (x + 2)^2 = [5 + (x + 2)][5 - (x + 2)]
= (7 + x)(3 - x)
2008-03-07 5:26 pm
25 - x^2 -4x - 4 = 0

x^2 + 4x - 21

(x + 7)(x - 3)
2008-03-07 5:02 pm
25-(x^2+4x+4)=0
(x+2)^2 =25
x+2 = sqrt(25)
x +2 = +/-5
x = 5 - 2
x = 3

and
x = -5 -2
x = -7
2008-03-07 4:53 pm
25 - (x^2 + 4x + 4)
(5^2) - ((x + 2)^2)
(5 + (x + 2))(5 - (x + 2))
(5 + x + 2)(5 - x - 2)
(7 + x)(3 - x)

Answer: (7 + x)(3 - x)
2008-03-07 5:02 pm
here you go
25-(x^2+4x+4)

= 25-x^2-4x-4

= -x^2 - 4x +21

= -(x^2 + 4x -21)

=(x + 7)(3 - x)
2008-03-07 4:50 pm
25 - (x^2 + 4x + 4)
= 25 - x^2 - 4x - 4
= -x^2 - 4x - 4 + 25
= -x^2 - 4x + 21
= (-x + 3)(x + 7)
2008-03-07 4:39 pm
(23-x)(25-x)


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