multiply (x+2)(x3-x2+x-2)?

(x+2)(x³ - x² + x - 2) =

(x^4 - x³ + x² - 2x) + (2x³ - 2x² + 2x - 4) =

x^4 + x³ - x² - 4

x^4 - x ³ + x ² - 2 x
___2x ³ - 2x ² + 2 x - 4

x^4 + x³ - x² - 4

If you mean to the third power, second power, etc. in the second bracket, it would be this:

x^4 + 3x^3 + 3x^2-4

If you mean 3x-2x etc. without the powers, this would be the answer:
6x^2+2x-4

Hope this helps!

i can help if you know what X equals. Do you know? if not combine the X with the other Xs in each () then work the problem.

(x+2)(x^3-x+x²+x-2)=x(x^3-x²+x-2)+2(x^3-x²+x-2)=x^4+x^3-x²-4

x^4-x^3+x^2-2x+2x^3-2x^2+2x-4=x^4+x^3-x^2+2x+4

(x + 2)(x^3 - x^2 + x - 2)
= x^4 + 2x^3 - x^3 - 2x^2 + x^2 + 2x - 2x - 4
= x^4 + x^3 - x^2 - 4

-2x