multiply (1-x+x2)(1-x+x2)?
回答 (10)
2008-03-06 2:05 pm
✔ 最佳答案
(1-x+x²)(1-x+x²) =(x^4 - x^3 + x^2) + (-x^3 + x^2 - x) + (x^2 - x + 1) =
x^4 - 2x^3 + 3x² - 2x + 1
2008-03-07 12:22 am
1 - x + x²
_- x + x² - x³
_____x² - x³ + x^4
1 - 2x + 3x² - 2x³ + x^4
_- x + x² - x³
_____x² - x³ + x^4
1 - 2x + 3x² - 2x³ + x^4
2008-03-06 10:14 pm
1-2x+3x2-2x3+x4
2008-03-06 10:08 pm
(1 - x + x^2)(1 - x + x^2)
= (x^2 - x + 1)(x^2 - x + 1)
= x^4 - x^3 + x^2 - x^3 + x^2 - x + x^2 - x + 1
= x^4 - x^3 - x^3 + x^2 + x^2 + x^2 - x - x + 1
= x^4 - 2x^3 + 3x^2 - 2x + 1
= (x^2 - x + 1)(x^2 - x + 1)
= x^4 - x^3 + x^2 - x^3 + x^2 - x + x^2 - x + 1
= x^4 - x^3 - x^3 + x^2 + x^2 + x^2 - x - x + 1
= x^4 - 2x^3 + 3x^2 - 2x + 1
2008-03-06 10:07 pm
1 - x + x^2 - x + x^2 - x^3 + x^2 - x^3 + x^4
= x^4 - 2x^3 + 3x^2 - 2x + 1
= x^4 - 2x^3 + 3x^2 - 2x + 1
2008-03-06 10:07 pm
If x2 is x*2 (multiplied), then (x-x2-1)^2
If x2 is x^2 (squared), then (x^2-x+1)^2
If x2 is x^2 (squared), then (x^2-x+1)^2
2008-03-06 11:24 pm
1-x+x²)(1-x+x²) =
(x^4 - x^3 + x^2) + (-x^3 + x^2 - x) + (x^2 - x + 1) =
x^4 - 2x^3 + 3x² - 2x + 1
(x^4 - x^3 + x^2) + (-x^3 + x^2 - x) + (x^2 - x + 1) =
x^4 - 2x^3 + 3x² - 2x + 1
2008-03-06 10:09 pm
(1-x+x²)(1-x+x²)=1(1-x+x²)-x(1-x+x²)+x²(1-x+x²)
=1-x+x²-x+x²-x^3+x²-x^3+x^4
Regrouping the terms we get it as x^4-2x^3+3x²-2x+1
=1-x+x²-x+x²-x^3+x²-x^3+x^4
Regrouping the terms we get it as x^4-2x^3+3x²-2x+1
2008-03-06 10:07 pm
(1-x+x2)(1-x+x2)
(1-x+x^2)+(-x+x^2+x^3)+(x^2+-x^3+x^4)
^^^Distributed each number and multiplied it to
the second number. I.E. 1x1, -x*-x
2x^4+x^3+3x^2+(x+-x)+1
^^Added common terms^^
x^4+2x^3+3x^2+1
(1-x+x^2)+(-x+x^2+x^3)+(x^2+-x^3+x^4)
^^^Distributed each number and multiplied it to
the second number. I.E. 1x1, -x*-x
2x^4+x^3+3x^2+(x+-x)+1
^^Added common terms^^
x^4+2x^3+3x^2+1
2008-03-06 10:07 pm
1-x+x^2-x+x^2-x^3+x^2-x^3+x^4
= x^4-2x^3+3x^2-2x+1
= x^4-2x^3+3x^2-2x+1
收錄日期: 2021-05-01 10:10:37
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